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| 1. |
The mass of a hoop of radius 0.30 m is 2kg. It rolls along a horizontal floor so that its centre of mass has a speed of 2 m/s. What is the work done to stop it ? |
| Answer» SOLUTION :Work `=(1//2)mv^(2) + (1//2)IOMEGA^(2)=(1//2)mv^(2) xx (V^(2)//R^(2)) =mv^(2) = 8 J` | |