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The mass of a non-volatile solute (Molar mass 40) which should be dissolved in `114g` octance to reduce its vapour pressure to `80%` is `2xg`. Find the value of `x` |
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Answer» Correct Answer - 5 5 `P_(S)=(80/100)P^(0),w=?,m=40` `W=114g,M_(C_(s)H_(18))=114` `(P^(0)-P_(s))/(P_(s))=(wxxM)/(mxxW)` Or `(P^(@)-(80/100)P^(@))/((80/100)P^(@))=(wxx114)/(40xx114)` `w=10g` |
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