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The mass of a non-volatile solute (molar mass 80 g mol^(-1) ) which should be dissolved in 92g of toluene to reduce its vapour pressure to 90% |
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Answer» Solution :`(Delta P)/(P^(@))=X_(2)` `(100-90)/(100)=(n_(2))/(n_(1)+n_(2))` `(1)/(10)=(n_(2))/(n_(1)+n_(2))` `(n_(2))/(n_(1)+n_(2))=10` `(n_(1))/(n_(2))+1 =10 "" [n_(1)=(92)/(92)=1]` `(1)/(n_(2))=9` `n_(2)=(1)/(9)` `(W_(2))/(M_(2))=(1)/(9)` `W_(2)=(M_(2))/(9)=(80)/(9)=8.89 g` |
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