The mass of a unifprm rod is 0.4 kg and its length is 2 m. .Calculate the radius of gyration of the rod about an axis passing through its centre of mass and perpendicular to its length ?

The mass of a unifprm rod is 0.4 kg and its length is 2 m. .Calculate

1.	The mass of a unifprm rod is 0.4 kg and its length is 2 m. .Calculate the radius of gyration of the rod about an axis passing through its centre of mass and perpendicular to its length ?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/mk-548207" style="font-weight:bold;" target="_blank" title="Click to know more about MK">MK</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = Ml^(2)//<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>, K = l//sqrt(12) = 2sqrt(12) = 0.58 m`</body></html>