1.

The mass of a unifprm rod is 0.4 kg and its length is 2 m. .Calculate the radius of gyration of the rod about an axis passing through its centre of mass and perpendicular to its length ?

Answer»


SOLUTION :`MK^(2) = Ml^(2)//12, K = l//sqrt(12) = 2sqrt(12) = 0.58 m`


Discussion

No Comment Found