1.

The mass of AgCl precipitated when a solution containing 11.70 g of NaCl is added to a solution containing 3.4g of AgNO_(3), is [Atomie mass of Ag -108, Atomic mass of Na - 23]

Answer»

5.74 g
1.17 g
2.87 g
6.8 g

SOLUTION :(c) : `NaCl + AgNO_(3) to AgCl+NaNO_(3)`
No. of MOLES : `(11.70)/(58.5) (3.4)/(170)`
= 0.2= 0.02= 0.02
Here, `AgNO_(3)` is limiting REAGENT.
`:.` Mass of AgCl precipitated = `0.02 XX 143.5 = 2.87` g


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