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The mass of an electron is 9.1xx10^(-31) kg. If its K.E. is 3.0xx10^(-25)J, calculate its wavelength. |
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Answer» Solution :`K.E.=1/2 MV^(2)` `:. V=sqrt((2 K.E.)/m)=sqrt((2xx3.0xx10^(-25) J)/(9.1xx10^(-31) KG))=812 ms^(-1)""(1 J=1 kg m^(2) s^(-2))` By de Broglie EQUATION, `lambda=h/(mv)=(6.626xx10^(-34) Js)/((9.1xx10^(-31) kg)(812 ms^(-1)))=8.967xx10^(-7) m=8967 Å` |
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