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The mass of `CaCO_(3)` produced when carbon dioxide is bubbled through 500 mL of 0.5 M `Ca(OH)_(2)` solution will be :A. 25 gB. 50 gC. 20 gD. 10 g |
Answer» Correct Answer - A Mass of `Ca(OH)_(2)` is calculated as follows : Molarity `= (("Mass of "Ca(OH)_(2))/("Molecular mass"))/("Volume of solution in litres")` `0.5=("Mass of "Ca(OH)_(2))/(74)xx(1000)/(500)` `=0.5xx39 = 18.5g` `{:(Ca(OH)_(2)+CO_(2),rarr,CaCO_(3)+H_(2)O),(74g,,100g),(18.5g,,(100)/(74)xx18.5=25g):}`. |
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