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The mass of `CaCO_(3)` produced when carbon dioxide is bubbled through 500 mL of `0*5 M` `Ca(OH)_(2)` will beA. 10 gB. 20 gC. 50 gD. 25 g |
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Answer» Correct Answer - D `Ca(OH)_(2)+CO_(2)toCaCO_(3)+H_(2)O` `Ca(OH)_(2) = 0*5xx500xx10^(-3)` moles `=0*25` mol Now 1 mole `Ca(OH)_(2)` gives `CaCO_(3) = 100g` `0*25` mole `Ca(OH)_(2)` gives `CaCO_(3)` `=0*25xx100=25g` |
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