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The mass of copper that will be deposited at cathode in electrolysis of `0.2M` solution of copper sulphate when a quantity of electricity equal to that required to liberate `2.24L` of hydrogen from `0.1M` aqueous `H_(2)SO_(4)` is passed `(` atomic mass of `Cu=63.5)` will beA. `1.59g`B. `3.18g`C. `6.35g`D. `12.70g`

Answer» Correct Answer - c
`1F=1Eq of H_(2)=11.2L of H_(2)`
`11.2L of H_(2)=1Eq of H_(2)`
`2.24 L of H_(2)=(2.24)/(11.2)=0.2Eq`
`:. 0.2 Eq of Cu` will be deposited.
`1Eq of Cu=(63.5)/(2)xx0.2=6.35g`


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