1.

The mass of glucose that should be dissolved in 50 g of water in order to produce the same lowering of vapour pressure as produced by dissolving 1 g of urea in the same quantity of water is

Answer»

<P>1 g
3 g
6 g
8 g

Solution :`(p^(@)-p_(s))/(p^(@))=(n_(2))/(n_(1))=(w_(2)M_(1))/(w_(1)M_(2))`
As (`p^(@)-p_(s))//p^(@)` is same in the two CASES
`((w_(2)M_(1))/(w_(1)M_(2)))_("glucose")=((w_(2)M_(1))/(w_(1)M_(2)))_("urea")`
`(w_(2)xx18)/(50xx180)=(1xx18)/(50xx60) or w_(2)=3 g.`


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