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The mass of molecule A is twice the mass of molecule B. The rms speed of A is twice the rms speed of B. If two samples of A and B contain same no. of molecules, what will be the ratio of P of two samples in separate containers of equal volume. |
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Answer» <P> Solution :Given, `M_(A) =2M_(B)``therefore` Mol wt. of `A=2xx` mol wt. of B `"…(1)"` `U_("rma")` of `A=2xxU_("rms")` of B `"…(2)"` Also, the no. of molecules of A =NO. of Molecules of B `"….(3)"` For GAS `A P_(A) V_(A) =(1)/(3) M_(A) U_("rms")^(2) A` `(P_(A)V_(A))/(P_(B)V_(B))=(M_(A))/(M_(B))xx(U_(A))/(U_(B))".....(4)"` Given `V_(A) =V_(B)".....(5)"` `therefore` By equation (1) (2) (4) & (5) `(P_(A))/(P_(B)) =2xx(2)^(2)=8` `P_(A) =8P_(B)` |
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