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The mass of oxalic acid crystals `(H_(2)C_(2)O_(4).2H_(2)O)` required to prepare 50 mL of a 0.2 N solution is:A. 126 gB. 12.6 gC. 63 gD. 6.3 g |
Answer» Correct Answer - D 1000 ml of 1 N oxalic solution = 63 g 500 ml of 0.2 N oxalic acid solution `=(63)/(1000)xx500xx0.2=6.3 g`. |
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