1.

The mass of oxygen that would be required to produce enough CO which completely reduces `1*6` kg `Fe_(2)O_(3)` (at. mass of Fe = 56)A. 240 gB. 480 gC. 720 gD. 960 g

Answer» Correct Answer - B
`3C+(3)/(2)O_(2)to3CO`,
`Fe_(2)O_(3)+3COto2Fe+3CO_(2)`
1 mol of `Fe_(2)O_(3) -= 3//2` mol of `O_(2)`
`160 g` (GMM) of `Fe_(2)O_(3)` required `O_(2) = (3)/(2)=32 = 48g`
`1*6` kg of `Fe_(2)O_(3)` required `O_(2) = 480g`


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