1.

The mass of potassium dichromate crystals required to oxidise 750 cm^3 of 0.6 M Mohr's salt solution is: (Given molar mass : potassium dichromate = 294, Mohr's salt = 392)

Answer»

0.45 g
22.05 g
2.2 g
0.49 g

Solution :GRAM EQUIV. of moh.s salt = gram equiv. of `K_2Cr_2O_7`
Gram equiv. of mohr.s salt in `750 cm^3` of 0.6 M solution
` = 0.6 xx 1 xx 750/1000`
= 0.45
Let the mass of `K_2Cr_2O_7 = X g `
` therefore(x)/(294//6)= 0.45`
`(becauseEq. wt of K_2Cr_2O_7 = ("mol. wt)/(6) )`
`x= (0.45 xx 294)/(6) = 22.05 g `


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