InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The mass of the liquid flowing per second per unit area of cross section of the tube is proportional to `P^(x) and v^(y)` , where `P` is the pressure difference and `v` is the velocity , then the relation between x and Y isA. ` x = y `B. ` x = -y`C. ` y^(2) = x`D. ` y = -x^(2)` |
|
Answer» Correct Answer - B `(M)/(At) prop P^(x) v^(y)` rArr `ML^(-2) T^(-1) = [ML^(-1)T^(-2)]^(x) [L^(1) T^(-1)]^(y) = M^(x) L^(-x + y )T^(-2 x - y)` ` x = 1 , -x + y = -2 , and -2x -y = -1` From here, we get `y = -1` . Thus , `x = -y`. |
|