The mathematical from of Chart.s law is given under V_(t)=V_(0)((273.15+t^(@)C)/(273^(@)C)), From this equation explain V to T in Kelvin.

The mathematical from of Chart.s law is given under V_(t)=V_(0)((273.1

1.	The mathematical from of Chart.s law is given under V_(t)=V_(0)((273.15+t^(@)C)/(273^(@)C)), From this equation explain V to T in Kelvin.
Answer» Solution :`V_(t)=V_(0)((273.15+t)/(273.15)) ""` ….(Eq. -i) `therefore V_(t)=(V_(0)(273))/(273)+(V_(0)t^(@)C)/(273)` `therefore V_(t)=V_(0)+((t^(@)C)/(273))V_(0) ""`…..(Eq. -II) As per equation `Y=C+mx` `therefore` The graph of VOLUME `(V) to` Temperature in Kelvin. Where, SLOPE `= tan theta = (V_(0))/(273)`, INTERCEPT `= V_(0)` Upward graph is straight.