The maximum amount of BaSO_(4) precipitated on mixing equal volumes of BaCl_(2) (0.5 M) with H_(2)SO_(4) (1 M) will correspond to

The maximum amount of BaSO_(4) precipitated on mixing equal volumes of

1.	The maximum amount of BaSO_(4) precipitated on mixing equal volumes of BaCl_(2) (0.5 M) with H_(2)SO_(4) (1 M) will correspond to
Answer» `0.5N` `1.0N` `1.5N` `2.0M` SOLUTION :Eq. `BaCl_(2)=Vxx0.5xx2=V` Eq. `H_(2)SO_(4)=Vxx1xx2=2V` `therefore` Max eq. of `BaSO_(4)=V` `[BaSO_(4)^(-)]=(V)/(2V)=0.5N`