InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The maximum and minimum amplitude of AM wave is found to be 15 V and 3 V , respectively . The amplitudes of carrier wave and modulating wave will beA. 9 and 6 VB. 6 and 9 VC. 18 and 9 VD. 24 and 16 V |
|
Answer» Correct Answer - A Given , `A_("max")=A_(c)+ A_(m)=15V ` .........(i) ` A _("min")=A_(c)-A_(m)=3V `.......... (ii) From Eq. (i) ` A_(c) =15-A_(m)`. Now , put it in Eq. (ii) ,we get ` 15-A_(m)-A_(m)=3 ` `implies 2A_(m)=12 ` `implies A_(m)=6V ` From Eqs . (i) `:. A_(c)=15-6=9V ` |
|