1.

The maximum areaof a rectangle (in m?)having perimeter1000 m is​

Answer»

length = 2lbreadth = 2b 2L + 2b = 1000 l + B = 500 l = 500 - b area of rectangle = l × b . = ( 500 - b)b = 500b-b^2 b^2 = 500b b = 500m l = 500 - 500 = 0M



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