1.

The maximum displacement of a particle executing SHM is 1 cm and the maximum acceleration is (1.57)^(2)cm//s^(2). Its time period is……………..

Answer»

0.25s
4.0s
1.57s
3.14s

Solution :`T=2pisqrt((A)/(a_(MAX)))=2xx3.14xxsqrt((1.0)/((1.57)^(2)))=4.0s`


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