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The maximum distance between the transmitting and receiving TV towers is `D`. If the heights of both transmitting and receiving towers are doubled then the maximum distance between them becomesA. `2D`B. `sqrt(2)D`C. `4D`D. `D//2` |
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Answer» Correct Answer - B `s=sqrt(2Rh_(T))+sqrt(2Rh_(R))` when both `h_(T)` and `h_(R)` are doubled then s becomes `sqrt(2) "times"`. |
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