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The maximum distance between the transmitting and receving TV towers is `72 km`. If the ratio of the heights of the TV transmitting tower to receiving tower is `16 : 25`, the heights of the transmitting and receiving tower areA. `51.2m`, `80m`B. `40 m` , `80 m`C. `80 m`, `125 m`D. `25 m` , `75 m` |
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Answer» Correct Answer - C `(h_(t))/(h_(r))=(16)/(25)`, `d=sqrt(2Rh_(t))+sqrt(2Rh_(r))` `72xx10^(3)=sqrt(2R(16)/(25)h_(r))+sqrt(2Rh_(r))` `impliesh_(r)=125m` & `h_(t)=80m` |
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