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The maximum height attained by the projectile is increased by 5%. Keeping the angle of projection constant. What is the percentage increased in the horizontal range. (a) 5% (b) 10% (c) 15% (d) 20% |
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Answer» Answer is (a) 5% If ym be the maximum height, then R = 4ym cotα.. therefore ∆R/R = ∆ym/ym. Hence percentage increase in range is also equal to 5%. |
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