The maximum kinetic energy of photoelectron liberated from the surface of lithium (work function = 2.35eV) by electromagnetic radiation whose electric component varies with time as E=a[1+cos(2πf1t)]cos(2πf2t) where ‘a’ is a constant, f1=1.2×1015Hz and f2=3.6×1015Hz is [Take: h=6.6×10−34 J s ]

The maximum kinetic energy of photoelectron liberated from the surface

1.	The maximum kinetic energy of photoelectron liberated from the surface of lithium (work function = 2.35eV) by electromagnetic radiation whose electric component varies with time as E=a[1+cos(2πf1t)]cos(2πf2t) where ‘a’ is a constant, f1=1.2×1015Hz and f2=3.6×1015Hz is [Take: h=6.6×10−34 J s ]
Answer» The maximum kinetic energy of photoelectron liberated from the surface of lithium (work function = 2.35eV) by electromagnetic radiation whose electric component varies with time as $E = a [1 + c o s (2 π f_{1} t)] c o s (2 π f_{2} t)$ where ‘a’ is a constant, $f_{1} = 1.2 \times 10^{15} H z$ and $f_{2} = 3.6 \times 10^{15} H z$ is [Take: $h = 6.6 \times 10^{- 34} J s$ ]

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