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The maximum load that a wire can sustain is W. If the wire is cut to half its value, the maximum load it can sustain isA. `W `B. `W/2`C. `W/4`D. `2W` |
Answer» Correct Answer - A `sigma_(max)= F_(max)/A` `:. F_(max) = F_(max)/A` , which is independent of length of wire. |
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