The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum number, m_(s) = -(1)/(2), is

The maximum number of electrons that can have principal quantum number

1.	The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum number, m_(s) = -(1)/(2), is
Answer» Solution :Number of orbitals in the SHELL with n = 3 will be `= n^(2) = 3^(2) = 9`. Each orbital can have maximum 2 electrons one with spin `+(1)/(2)` and the other with `- (1)/(2)`. HENCE, number of electrons with `m_(s) = - (1)/(2)` will be 9