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The maximum number of electrons that can have principal quantum number, n = 3, and spin quantum number, `m_(s) = -(1)/(2)`, is |
Answer» Correct Answer - 9 Number of orbitals in the shell with n = 3 will be `= n^(2) = 3^(2) = 9`. Each orbital can have maximum 2 electrons one with spin `+(1)/(2)` and the other with `- (1)/(2)`. Hence, number of electrons with `m_(s) = - (1)/(2)` will be 9 |
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