1.

The maximum number of molecules is present in:

Answer»

15L of `H_(2)` gas at STP
5L of `N_(2)` gas at STP
0.5 g of `H_(2)` gas
10 g of `O_(2)` gas

Solution :Number of molecules in 15L `H_(2)=(15)/(22.4)XxN=0.669N`
Number of molecules in 5L `N_(2)=(5)/(22.4)xxN=0.223N`
Number of molecules in 0.5 g `H_(2)=(0.5)/(2)xxN=0.25N`
Number of molecuels in `10g O_(2)=(10)/(32)xxN=0.312N`


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