The maximum range of a projectile is 2/√3 times its actual range. Wh – InterviewSolution

1.

The maximum range of a projectile is 2/√3 times its actual range. What is the angle of projection for the actual range?

Answer»

u²/g = u² sin 20/g x 2/√3

or, sin 20 = √3/2

or 20 = 60°

or, θ = 30°.

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