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The maximum value of 3 sin^2 X+5 COS^2 X |
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Answer» 3 is the MAXIMUM valueExplanation: using the identitysin*2x+cos*2x=13sin*2x+5cos*2x3sin*2x+5(1-sin*2x)5-2sin*2x(since maximum value of SINX is 1)5-2(1)*2=3 |
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