InterviewSolution
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InterviewSolution
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The maximum value of `f(x)=(2x^2+2x+4)/(x^2+x+1) AA x in [0,1] is ` |
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Answer» `f(x) = (2x^2+2x+4)/(x^2+x+1)` `=>f(x) = (2(x^2+x+2))/(x^2+x+1)` `=>f(x) = (2(x^2+x+1+1))/(x^2+x+1)` `=>f(x) = 2(1+1/(x^2+x+1))` Now, `f(x)` will be maximum when `x^2+x+1` is minimum. Now, we will try to draw the graph for `x^2+x+1.` Please refer to video to see the grah. From the graph, we can see that minimum value of `x^2+x+1` is `1` as `x in [0,1]`. `:. f(x)_max = 2(1+1/1) = 4` |
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