1.

The maximum value of z in the following equation z=6xy+y2, where 3x+4y≤100 and 4x+3y≤75 for x≥0 and y≥0 is

Answer» The maximum value of z in the following equation z=6xy+y2, where 3x+4y100 and 4x+3y75 for x0 and y0 is


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