InterviewSolution
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InterviewSolution
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The maximum velocity and maximum acceleration of a particle per for ming a linear SHM are `alpha and beta` respectively. Then path length of the particle isA. `(alpha^(2))/(beta)`B. `(beta)/(2 alpha^(2))`C. `(2 alpha^(2))/(beta)`D. `(2 beta)/(alpha^(2))` |
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Answer» Correct Answer - C `alpha = V_(max)=A omega and a_(max)=A omega^(2) = beta` `therefore" "(alpha^(2))/(beta)=(A^(2)omega^(2))/(Aomega^(2))=A` `therefore` Path length `= (2 alpha^(2))/(beta)` |
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