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The maximum velocity and maximum acceleration of a particle executing SHM are 20 cm `s^(-1) and 100 cm s^(-2)`. The displacement of the particle from the mean position when its speed is 10 cm `s^(-1)` isA. 2 cmB. 2.5 cmC. `2sqrt(3) cm`D. `2sqrt(2) cm` |
Answer» Correct Answer - C `V_(m)=Aomega=20cms^(-1)` `a_(m)=Aomega^(2)=100cms^(-2)` `(V_(m)^(2))/(a_(m))=A=(400)/(100)=4cm` `(a_(m))/(V_(m))=omega=(100)/(20)=5" rad/s"` `V=omegasqrt(A^(2)-y^(2)),10=5sqrt(4^(2)-y^(2))` `4=4^(2)-y^(2),y^(2)=4^(2)-4=12,y=2sqrt(3)cm` |
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