The maximum work obtained by an isothermal reversible expansion of 1 m – InterviewSolution

1.	The maximum work obtained by an isothermal reversible expansion of 1 mol of an ideal gas at 27^(@)C from 2.24 to 22.4L is (R = 2 cal)
Answer» 1381.8 cal 600 cal 138.18 cal 690.9 cal Solution :`w = nRT "LN" (V_(2))/(V_(1))` `= 1 XX 2 xx 300 x 2.303 "LOG" (22.4)/(2.4)` `= 1381.8 cal`

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