1.

The Mean And The Variance Of A Binomial Distribution Are 4 And 2 Respectively. Then The Probability Of 2 Successes Is?

Answer»

<P>Given that variance npq = 2

and MEAN NP = 4

q = 1/2

=> p = 1/2

n = 8

=> 8c2 * (1/2)^8 = 28/256

ans = 28/256

Given that variance npq = 2

and mean np = 4

q = 1/2

=> p = 1/2

n = 8

=> 8c2 * (1/2)^8 = 28/256

ans = 28/256


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