1.

The mean free path of electrons in a metal is `4 xx 10^(-8)m` The electric field which can give on an average `2eV` energy to an electron in the metal will be in the units `V//m`A. `5 xx 10^(-11)`B. `8 xx 10^(-11)`C. `5 xx 10^(7)`D. `8 xx 10^(7)`

Answer» Correct Answer - c
Average energy = workdone `= q E lambda`
`:. 2eV = eE xx 4 xx 10^(-8)`
or `E = (2)/(4 xx 10^(-8)m) = 8 xx 10^(7)Vm^(-1)`


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