The mean monthly salary paid to all employees in a certain company was Rs. 600. The mean monthly salaries paid to male and female employees were Rs. 620 and Rs. 520 respectively. Find the percentage of male to female employees in the company.

The mean monthly salary paid to all employees in a certain company was

1.	The mean monthly salary paid to all employees in a certain company was Rs. 600. The mean monthly salaries paid to male and female employees were Rs. 620 and Rs. 520 respectively. Find the percentage of male to female employees in the company.
Answer» <html><body><p></p>Solution :Given: `barX_(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)=<a href="https://interviewquestions.tuteehub.com/tag/600-329515" style="font-weight:bold;" target="_blank" title="Click to know more about 600">600</a>,barX_(1)=620,barX_(2)=520` <br/> `"Let "N_(1)` =Male Employees and `N_(2)` = Female Employees <br/> Using the <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> of combined arithmetic mean, we have <br/> `barX_(12)=(barX_(1)N_(1)+barX_(2)N_(2))/(N_(1)+N_(2))`<br/> `600=((620)N_(1)+(520)N_(2))/(N_(1)+N_(2))` <br/> Or, `600(N_(1)+N_(2))=620N_(1)+520N_(2)` <br/> Or, `600N_(1)+600N_(2)=620N_(1)+520N_(2)` <br/> Or, `600N_(2)-520 N_(2)=620N_(1)-600N_(1)` <br/> `""80N_(2)=20N_(1)` <br/> Or,` ""N_(1)/N_(2)=80/20=4/1` <br/> Or, `""N_(1):N_(2)= 4:1` <br/> Hence, the percentage of male employees = ` 4/(4+1) xx 100 = 80%` <br/> and the percentage of female employees= `1/(4+1) xx 100 = 20%`.</body></html>