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The mean of 5 observations is 7. Later on, it was found that two observations 4 and 8 were wrongly taken instead of 5 and 9. Find the corrected mean. |
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Answer» Solution :GIVEN: `N =5, barX=7` `""barX=(sumX)/N` Or, `""sum X=N XX barX` `:.""sumX"(Wrong)" = 5 xx 7 = 35` CORRECT `sumX = 35` + Correct items - Incorrect items `""=35+5+9-4-8=37` Correct `barX=("Correct" sumX)/N= 37/5` `= 7.4` Thus, Corrected Mean = `7.4`. |
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