1.

The mean of 50 observation is 36. if two observation 30 and 42 are to be excluded, then the mena of the reamining observations will be-A. 36B. 38C. 48D. 50

Answer» Correct Answer - A
`barx=(sumX_(i))/(n)`
`36=(sumX_(i))/(50)rArrsumX_(i)=1800`
Now `sumX_(i)-(42+30)=1728`
new mean `=(1728)/(48)=36`


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