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    				| 1. | The mean of a binomial distribution is 5 and the standard deviation is 2. Determine the distribution. | 
| Answer» Given mean = 5 and standard deviation = 2 (i.e,) np = 5 and √npq = 2 ⇒ npq = 4 5q = 4 ⇒ q = , p = 1 – 4/5 = 1/5 Again np = 5 gives = 5 ⇒ n = 25 So the p.m.f of the distribution is given by P (X = x) = (25, x)(1/5)x(4/5)25-x | |