1.

The mean radius of a planet is `6.67xx10^(3)` km. The acceleration due to gravity on its surface is `10 m//s^(2)`. If `G = 6.67xx10^(-11)Nm^(2)//kg^(2)`, then the mass of the planet will be `[R=6.67xx10^(6)m]`A. `6.67xx10^(20)kg`B. `6.67xx10^(24)kg`C. `9.8xx10^(23)kg`D. `13.34xx10^(23)kg`

Answer» Correct Answer - B
`g=(GM)/(R^(2))`
`R=6.67xx10^(3)km = 6.67xx10^(6)m`
`therefore M = (gR^(2))/(G)=(10xx6.67xx10^(6)xx6.67xx10^(6))/(6.67xx10^(-11))`
`= 6.67xx10^(24)kg`


Discussion

No Comment Found

Related InterviewSolutions