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The mean radius of a planet is `6.67xx10^(3)` km. The acceleration due to gravity on its surface is `10 m//s^(2)`. If `G = 6.67xx10^(-11)Nm^(2)//kg^(2)`, then the mass of the planet will be `[R=6.67xx10^(6)m]`A. `6.67xx10^(20)kg`B. `6.67xx10^(24)kg`C. `9.8xx10^(23)kg`D. `13.34xx10^(23)kg` |
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Answer» Correct Answer - B `g=(GM)/(R^(2))` `R=6.67xx10^(3)km = 6.67xx10^(6)m` `therefore M = (gR^(2))/(G)=(10xx6.67xx10^(6)xx6.67xx10^(6))/(6.67xx10^(-11))` `= 6.67xx10^(24)kg` |
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