1.

The measured mass and volume of a body are 2.42 g and 4.7 cm^(3) respectively with possible errors 0.01g and 0.1 cm^(3). Find the maximum error in density.

Answer»

Solution :Density,`d=(mass(m))/(VOLUME(V))`
Here `m=2.42g, Deltam=0.01g,v=4.7cm^(3)` , `DeltaV =0.1cc`
Maximum error in density,`(DELTAD)/d XX100=((Deltam)/mxx100)+((DeltaV)/Vxx100)`
`=((0.01)/(2.42)xx100)+((0.1)/(4.7)xx100)=0.413%+2.127%=2.54%`


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