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The measured resistance of a conductance cell containing 7.5xx10^(-3)M solution of KCl at 25^(@)C was 1005 ohms. Calculate (a) specific conductance (b) molar conductance of the solution. Cell constant=1.25 cm^(-1). |
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Answer» Solution :Specific coductance `(kappa)=(1)/(R)XX"CELL constant"=(1)/(1005Omega)xx1.25cm^(-1)=0.001244Omega^(-1)cm^(-1)` Molar conductance `(wedge_(m))=(kappaxx1000)/("Molarity")=(0.001244Omega^(-1)cm^(-1)xx1000cm^(3)L^(-1))/(7.5xx10^(-3)molL^(-1))` `=165.87Omega^(-1)cm^(2)mol^(-1)` |
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