The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988^(@)C` . The principla reason that melting point of `NaF` is much higher than that of `RbBr` is that `:`A. the two crystals are not isomorphousB. the molar mass of NaF is smaller than that of RbBrC. the bond in RbBr has more covalent character than the bond in NaFD. the internuclear distance `(r_(c)+r_(a))` is greater for RbBr than for NaF.

The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988

1.	The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988^(@)C` . The principla reason that melting point of `NaF` is much higher than that of `RbBr` is that `:`A. the two crystals are not isomorphousB. the molar mass of NaF is smaller than that of RbBrC. the bond in RbBr has more covalent character than the bond in NaFD. the internuclear distance `(r_(c)+r_(a))` is greater for RbBr than for NaF.
Answer» Correct Answer - D Lattice energy is inversely proportional to inter ionic distance and so is the melting point of a crystalline solid.

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