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The metal ion in complex `underline(A ) ` has EAN identical to the atomic number of krypton . `underline (A) ` is ( Atomic no. Of `Cr =24,Fe=26 ,pd =46) `A. `[Pd(NH_(3))_(6)]Cl_(4)`B. `[Cr(NH_(3))_(5)Cl]SO_(4) `C. `Na_(4)[Fe(CN)_(6)]`D. `K_(3)[Fe(CN)_(6)]` |
Answer» Correct Answer - C EAN =`Z-(o .N ) +2 (C .N) x` Electrons donated by `CN^(-) ` where ,ON = oxidation number Z = atomic numebr ` [Fe(CN)_(6)]^(4-) :EAN = 26-(2) +2(6) - 2+12=36` |
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