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The middle term of arithmatic series 2, 6, 10, ...,1461. 702. 793. 744. 83 |
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Answer» Correct Answer - Option 3 : 74 Concept: Let us consider sequence a1, a2, a3 …. an is an A.P.
Calculation: Given series is 2, 6, 10, ...,146 First term, a = 2, last term, an = 146, an Common difference d = 4, so it is an AP an = a + (n – 1) d 146 = 2 + (n - 1) (4) ⇒ n - 1 = 144/4 ⇒ n = 36 + 1 = 37 So, number of terms in given series = 37 Middle term = (37 + 1)/2 = 19th term a19 = 2 + (19 - 1) × 4 = 2 + 72 = 74 Hence, option (3) is correct. |
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