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The minimum .............. |
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Answer» `y-tan alpha= (-1)/(sec^(2) alpha) (x-alpha)` `tan alpha. (sec^(2) alpha)=(2+pi/4-alpha)` `tan alpha (1+tan^(2) alpha)= (2+pi/4-alpha)` `alpha=pi/4` `implies` minimum DISTANCE = distance between `(pi/4, 1)` and `(2+pi/4, 0)` - RADIUS `=SQRT(5)-1` |
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