The minimum force required to start pushing a body up a rough (frictional coefficient mu) inclined plane is F_(1) while the minimum force needed to prevent it from sliding down is F_(2). If the inclined plane makes an angle theta with the horizontal such that tan theta = 2mu, then the ratio (F_(1))/(F_(2)) is

The minimum force required to start pushing a body up a rough (frictio

1.	The minimum force required to start pushing a body up a rough (frictional coefficient mu) inclined plane is F_(1) while the minimum force needed to prevent it from sliding down is F_(2). If the inclined plane makes an angle theta with the horizontal such that tan theta = 2mu, then the ratio (F_(1))/(F_(2)) is
Answer» 4 1 2 3 Solution :`F_("Up")=mg(SINTHETA +mu_(k)cos theta)`, `F_("down")=mg(sin theta-mu_(k)cos theta)`.