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The minimum power of the eye lens is 40 D. If the far point of the normal eye is infinity. Find the size of the eye ball. |
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Answer» Power of eye lens = P P = 40 D Focal length = f f = \(\frac{1}{P}\) (in meters) f = \(\frac{1}{40}\) = 0.025 m = 2.5 cm Radius of curvature = 2f = 5 cm The eye ball has the radius of 5 cm |
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